What is the de Broglie wavelength of an electron traveling at 2.0⋅108m/s?
1 Answer
Jun 24, 2017
Explanation:
de Broglie wave equation
...where
-
λ is the wavelength inm . -
p (mass(m)⋅velocity(v) ) is momentum
(electron mass =9.109⋅10−31 kg ). -
h is Planck's constant=6.626⋅10−34J(joule)⋅s(second) .
(1 Joule =1 kg⋅m2/s2 )
Resolving...
λ=6.626⋅10−34J⋅smv
λ=6.626⋅10−34J⋅s(9.109⋅10−31kg)(2.0⋅108m/s)
λ=6.626⋅10−34kg⋅m2/s18.2⋅10−23kg⋅m/s
Here, everything is cancelled except
λ=3.64⋅10−12 m
