What is the conjugated base in the following acid/base reaction: $C H_{3} C O O H + H_{2} O ⇌ H_{3} O^{+} + C H_{3} C O O^{-}$ $CH_3COOH + H_2O rightleftharpoons H_3O^+ + CH_3COO^-$ ?

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Answer 1 · 2016-12-09T13:00:29

A conjugate base is the particles that remained when a proton (H+) is removed from an acid.

This is based on the Bronsted-Lowry Acid theory where an acid donates a proton and a base accepts the proton.

Here, the conjugate base is $C H 3 C O O^{-}$ $CH3COO^-$ as it loses a hydrogen atom - loses a proton.

What is the conjugated base in the following acid/base reaction: CH3COOH+H2O⇌H3O++CH3COO−CH_3COOH + H_2O rightleftharpoons H_3O^+ + CH_3COO^-?