What is the conjugate of the square root of 2 + the square root of 3 + the square root of 5?

1 Answer
May 31, 2015

sqrt(2)+sqrt(3)+sqrt(5) does not have one conjugate. If you are trying to eliminate it from a denominator, then you need to multiply by something like:

(sqrt(2)+sqrt(3)-sqrt(5))(sqrt(2)-sqrt(3)+sqrt(5))(sqrt(2)-sqrt(3)-sqrt(5))

The product of (sqrt(2)+sqrt(3)+sqrt(5)) and this is -24