What is the conjugate of the square root of 2 + the square root of 3 + the square root of 5?

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What is the conjugate of the square root of 2 + the square root of 3 + the square root of 5?

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Answer 1 · 2015-05-31T20:42:56

#sqrt(2)+sqrt(3)+sqrt(5)# does not have one conjugate. If you are trying to eliminate it from a denominator, then you need to multiply by something like:

#(sqrt(2)+sqrt(3)-sqrt(5))(sqrt(2)-sqrt(3)+sqrt(5))(sqrt(2)-sqrt(3)-sqrt(5))#

The product of #(sqrt(2)+sqrt(3)+sqrt(5))# and this is #-24#

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What is the conjugate of the square root of 2 + the square root of 3 + the square root of 5?

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