What is the conjugate of the square root of 2 + the square root of 3 + the square root of 5? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer George C. May 31, 2015 sqrt(2)+sqrt(3)+sqrt(5) does not have one conjugate. If you are trying to eliminate it from a denominator, then you need to multiply by something like: (sqrt(2)+sqrt(3)-sqrt(5))(sqrt(2)-sqrt(3)+sqrt(5))(sqrt(2)-sqrt(3)-sqrt(5)) The product of (sqrt(2)+sqrt(3)+sqrt(5)) and this is -24 Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 8582 views around the world You can reuse this answer Creative Commons License