What is the conjugate acid and base of $H N_{3}$ $HN_3$ ?

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Answer 1 · 2016-08-10T04:19:02

$H N_{3}$ $HN_3$ is hydrazoic acid or azidic acid .

The conjugate base is $N_{3}^{-}$ $N_3^-$ , azide ion.

The conjugate acid could be accessed by magic acid, but given the instability of both components, I would not want to do that rxn:

$H N = N = N + H S b C l_{6} \to {[H_{2} N = N = N]}_{2}^{+} {(S b C l_{6})}_{6}^{-}$ $HN=N=N + HSbCl_6 rarr [H_2N=N=N]^+ (SbCl_6)^−$

What is the conjugate acid and base of HN3HN_3?