What is the concentration of the unknown H3PO4 solution? The neutralization reaction is H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4(aq)

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What is the concentration of the unknown H3PO4 solution? The neutralization reaction is H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4(aq)

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Answer 1 · 2017-06-12T18:38:23

For a start your reaction is.........

$H_{3} P O_{4} (a q) + 2 N a O H (a q) \to N a_{2} H P O_{4} (a q) + 2 H_{2} O$ $H_3PO_4(aq) + 2NaOH(aq) rarr Na_2HPO_4(aq) + 2H_2O$

Explanation:

Phosphoric acid is a DIACID in aqueous solution; and you should point this out to your prof.

And thus $moles of NaOH = 26.28 \times 10^{- 3} L \times 0.100 \cdot m o l \cdot L^{- 1}$ $"moles of NaOH"=26.28xx10^-3Lxx0.100*mol*L^-1$

$\equiv 2.63 \times 10^{- 3} \cdot m o l$ $-=2.63xx10^-3*mol$

And thus $concentration H_{3} P O_{4} = \frac{2.63 \times 10^{- 3} \cdot m o l \times \frac{1}{2}}{32.00 \times 10^{- 3} L}$ $"concentration "H_3PO_4=(2.63xx10^-3*molxx1/2)/(32.00xx10^-3L)$

$= 4.11 \times 10^{- 2} \cdot m o l \cdot L^{- 1} .$ $=4.11xx10^-2*mol*L^-1.$

$I reiterate that phosphoric acid is a diacid and not a triacid.$ $"I reiterate that phosphoric acid is a diacid and not a triacid."$

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What is the concentration of the unknown H3PO4 solution? The neutralization reaction is H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4(aq)

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