What is the concentration of nitric acid in the solution?

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What is the concentration of nitric acid in the solution?

14 $d m^{3}$ $dm^3$ of nitric acid is mixed with $250 c m^{3}$ $250 cm^3$ of $3.0 m o l$ $3.0mol$ $d m^{- 3}$ $dm^-3$ of calcium hydroxide, what is the concentration of nitric acid in the solution?

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Answer 1 · 2018-01-25T21:44:37

You have not laid out the starting conditions of the problem....

Explanation:

We assume that the nitric acid is NEUTRALIZED by the addition of the calcium hydroxide.

We need a stoichiometric equation:

$C a {(O H)}_{2} (a q) + 2 H N O_{3} (a q) \to C a {(N O_{3})}_{2} (a q) + 2 H_{2} O (l)$ $Ca(OH)_2(aq) + 2HNO_3(aq) rarrCa(NO_3)_2(aq) + 2H_2O(l)$

$Moles of calcium hydroxide = 250 \cdot c m^{3} \times 10^{- 3} \cdot d m^{3} \cdot c m^{- 3} \times 3 \cdot m o l \cdot d m^{3} = 0.750 \cdot m o l$ $"Moles of calcium hydroxide"=250*cm^3xx10^-3*dm^3*cm^-3xx3*mol*dm^3=0.750*mol$ .

And so there are TWO equiv of nitric acid...that are dissolved in the $14 \cdot d m^{3}$ $14*dm^3$ volume...i.e. $1.50 \cdot m o l$ $1.50*mol$

${Concentration}_{nitric acid} = \frac{1.50 \cdot m o l}{14 \cdot d m^{3}} = 0.107 \cdot m o l \cdot d m^{- 3}$ $"Concentration"_"nitric acid"=(1.50*mol)/(14*dm^3)=0.107*mol*dm^-3$

The question is poor, and does not reflect chemical reality. Calcium hydroxide is rather insoluble in aqueous solution, and would not support a concentration of $3.0 \cdot m o l \cdot d m^{- 3}$ $3.0*mol*dm^-3$ ... You should point this out to your teacher for brownie points...

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What is the concentration of nitric acid in the solution?

14 $d m^{3}$ $dm^3$ of nitric acid is mixed with $250 c m^{3}$ $250 cm^3$ of $3.0 m o l$ $3.0mol$ $d m^{- 3}$ $dm^-3$ of calcium hydroxide, what is the concentration of nitric acid in the solution?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

What is the concentration of nitric acid in the solution?

14 dm3dm^3 of nitric acid is mixed with 250cm3250 cm^3 of 3.0mol3.0mol dm−3dm^-3 of calcium hydroxide, what is the concentration of nitric acid in the solution?

1 Answer

Explanation:

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14 $d m^{3}$ $dm^3$ of nitric acid is mixed with $250 c m^{3}$ $250 cm^3$ of $3.0 m o l$ $3.0mol$ $d m^{- 3}$ $dm^-3$ of calcium hydroxide, what is the concentration of nitric acid in the solution?