What is the complex conjugate of $8 - sqrt3$ ?

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Answer 1 · 2017-07-23T07:19:59

Complex conjugate of $8-sqrt3$ is $8-sqrt3$ , itself.

Complex conjugate of a number $a+ib$ , where $a$ and $b$ are two real numbers and $i$ is imaginary number such that $i^2=-1$ , is $a-ib$

Here we just have a real number $8-sqrt3$ i.e. our complex number does not have imaginary part, whose sign changes in its conjugate.

Hence complex conjugate of $8-sqrt3$ is $8-sqrt3$ , itself.

What is the complex conjugate of 8 - sqrt38 - sqrt3?