What is the irrational conjugate of #1+sqrt8#? complex conjugate of #1 + sqrt(-8)#?

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Answer 1 · 2016-08-15T01:49:52

#1-sqrt 8 and 1-sqrt(-8)=1-i sqrt 8#, where i symbolizes #sqrt(-1)#.

The conjugate of the irrational number in the form

#a+bsqrt c#,

where c is positive and a, b and c are rational (including computer

string-approximations to irrational and transcendental numbers) is

a-bsqrt c#'

When c is negative, the number is termed complex and the

conjugate is

#a+ibsqrt(|c|)#, where# i = sqrt(-1)#.

Here, the answer is

#1-sqrt 8 and 1-sqrt(-8)=1-i sqrt 8#, where i symbolizes #sqrt(-1)#