What is the centroid of a triangle with corners at #(3, 1 )#, #(5, 2 )#, and #(12 , 6 )#?

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What is the centroid of a triangle with corners at #(3, 1 )#, #(5, 2 )#, and #(12 , 6 )#?

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Answer 1 · 2016-05-16T09:00:41

Centroid of the triangle is#(6 2/3,3)#

Explanation:

The centroid of a triangle whose vertices are #(x_1,y_1)#, (x_2,y_2)# and (x_3,y_3)# is given by

#((x_1+x_2+x_3)/3,(y_1+y_2+y_3)/3)#

Hence centroid of the triangle formed by points #(3,1)#, #(5,2)# and #12,6)# is #((3+5+12)/3,(1+2+6)/3)# or #(20/3,3)# or #(6 2/3,3)#

[For detailed proof for the formula see here.](http://www.learnnext.com/nganswers/ask-question/answer/How-to-derive-the-formula-of-centroid-from-section-formula/Coordinate-Geometry/84881.htm)

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What is the centroid of a triangle with corners at #(3, 1 )#, #(5, 2 )#, and #(12 , 6 )#?

1 Answer

Explanation:

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