What is the center of the circle given by the equation #(x - 3)^2 + (y - 9)^2 = 16#?

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Answer 1 · 2018-03-02T18:50:16

#(3,9)#

The standard form of the equation for a circle is given by:

#(x-h)^2+(y-k)^2=r^2#

Where:

#bbh# is the #bbx# coordinate of the centre.

#bbk# is the #bby# coordinate of the centre.

#bbr# is the radius.

From given equation we can see that the centre is at:

#(h,k)=(3,9)#