What is the center and radius of the circle with equation #(x-2)^2 + (y-5)^2=100#?
1 Answer
Jan 31, 2016
centre = (2 , 5 ) and r = 10
Explanation:
The standard form of the equation of a circle is :
# ( x - a )^2 + ( y - b )^2 = r^2 # where (a , b ) is the centre and r , the radius.
compare with :
# (x - 2 )^2 + (y - 5 )^2 = 100 # to obtain a = 2 , b = 5 and
# r = sqrt100 = 10 #
