What is the axis of symmetry of the graph of #y=-(x+3)^2-6#?

1 Answer
MeneerNask
May 26, 2015

If you complete the square, as was done in this case, it's not hard.
It's also easy to find the vertex.

#(x+3)# means that the parabola is displaced #3# to the left as compared to the standard-parabola #y=x^2#
(because #x=-3# would make #(x+3)=0#)

[It is also displaced #6# down, and the minus in front of the square means it's upside down, but that has no influence on the symmetry-axis, ]

So the axis of symmetry lies at #x=-3#
And the vertex is #(-3,-6)#
graph{-(x+3)^2-6 [-16.77, 15.27, -14.97, 1.05]}

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