What is the area enclosed by #r=-sin(theta+(15pi)/8) -theta# between #theta in [0,(pi)/2]#?

Related questions

• How do you find the area of the region bounded by the polar curve #r=3cos(theta)# ?
• How do you find the area of the region bounded by the polar curve #r=3(1+cos(theta))# ?
• How do you find the area of the region bounded by the polar curve #r=2-sin(theta)# ?
• How do you find the area of the region bounded by the polar curve #r^2=4cos(2theta)# ?
• How do you find the area of the region bounded by the polar curve #r=2+cos(2theta)# ?
• How do you find the area of the region bounded by the polar curves #r=sqrt(3)cos(theta)# and...
• How do you find the area of the region bounded by the polar curves #r=1+cos(theta)# and...
• How do you find the area of the region bounded by the polar curves #r=cos(2theta)# and #r=sin(2theta)# ?
• How do you find the area of the region bounded by the polar curves #r^2=cos(2theta)# and...
• How do you find the area of the region bounded by the polar curves #r=3+2cos(theta)# and...