What is the area enclosed by #r=5sin(-6theta-(5pi)/8) -2theta# between #theta in [pi/8,(3pi)/4]#?
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"How do you find the area of the region bounded by the polar curves #r=1+cos(theta)# and #r=1-cos(theta)# ?"
1 Answer
Oct 16, 2017
See the answer below:
