What is the area enclosed by #r=-3sin(2theta-(2pi)/4) -theta# between #theta in [pi/8,(3pi)/4]#? Calculus Polar Curves Calculating Polar Areas 1 Answer Frederico Guizini S. Apr 9, 2017 See the answer below: Answer link Related questions How do you find the area of the region bounded by the polar curve #r=3cos(theta)# ? How do you find the area of the region bounded by the polar curve #r=3(1+cos(theta))# ? How do you find the area of the region bounded by the polar curve #r=2-sin(theta)# ? How do you find the area of the region bounded by the polar curve #r^2=4cos(2theta)# ? How do you find the area of the region bounded by the polar curve #r=2+cos(2theta)# ? How do you find the area of the region bounded by the polar curves #r=sqrt(3)cos(theta)# and... How do you find the area of the region bounded by the polar curves #r=1+cos(theta)# and... How do you find the area of the region bounded by the polar curves #r=cos(2theta)# and #r=sin(2theta)# ? How do you find the area of the region bounded by the polar curves #r^2=cos(2theta)# and... How do you find the area of the region bounded by the polar curves #r=3+2cos(theta)# and... See all questions in Calculating Polar Areas Impact of this question 1767 views around the world You can reuse this answer Creative Commons License