What is the arclength of #f(x)=x^5-x^4+x # in the interval #[0,1]#?
1 Answer
May 12, 2016
approximately
Explanation:
The arc length of the function
#s=int_a^bsqrt(1+(f'(x))^2)dx#
So, here, we see that since
#s=int_0^1sqrt(1+(5x^4-4x^3+1)^2)dx#
This can't be integrated by hand, so stick it into a calculator to see that
#sapprox1.42326#
