# What is the arc length of f(x)=x^2/12 + x^(-1) on x in [2,3]?

$\approx 1.03425$
$f ' \left(x\right) = \frac{1}{6} x - \frac{1}{x} ^ 2$
${\int}_{2}^{3} \sqrt{1 + {\left(\frac{1}{6} \cdot x - \frac{1}{x} ^ 2\right)}^{2}} \mathrm{dx} \approx 1.03425$