What is the antiderivative of # 1/x^3#?

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What is the antiderivative of # 1/x^3#?

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Answer 1 · 2016-08-14T03:09:11

I found: #-1/(2x^2)+c#

Explanation:

You can write am Indefinite Integral as:
#int1/x^3dx=#
and solve it to find:
#=intx^-3dx=x^(-3+1)/(-3+1)+c=x^-2/-2+c=-1/(2x^2)+c#
If you derive this result you'll find your original #1/x^3# function.

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What is the antiderivative of # 1/x^3#?

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