What is the angular momentum of a rod with a mass of $8 kg$ and length of $7 m$ that is spinning around its center at $19 Hz$ ?

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Answer 1 · 2018-01-28T10:00:50

$4387.23(kgm^2)/s$

The angular momentum of a rod is given by $L=Iomega$ , where $I$ is the moment of inertia and $omega$ the angular velocity.

Furthermore, $I=1/12ml^2$ , where $m$ is the mass and $l$ the length of the rod.

Also, $omega=2pif$ , where $f$ is the frequency.

Calculate $I$ .

$I=1/12(8)(7)^2$
$color(white)I=3/4(49)$
$I=36.75kgm^2$

Calculate $omega$ .

$omega=2pi(19)$
$omega=38pi(rad)/s$

Using these values, multiply:

$L=Iomega$
$L=36.75*38pi$
$L=4387.23(kgm^2)/s$

What is the angular momentum of a rod with a mass of 8 kg8 kg and length of 7 m7 m that is spinning around its center at 19 Hz19 Hz?