What is the angular momentum of a rod with a mass of $8 kg$ and length of $6 m$ that is spinning around its center at $2 Hz$ ?

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Answer 1 · 2016-08-13T20:24:27

$"The angular momentum of rod is " 96pi$

$"The angular momentum of a rod spinning its center can be calculated using " L=I*omega$

$L:"represents angular momentum"$
$I:"represents moment of inertia"$
$omega:"represents angular velocity "$

$omega=2*pi*f" where f is frequency"$

$omega=2*pi*2=4pi$

$I=1/12*m*l^2(" moment of inertia for a rod spinning around its center")$

$m=8" kg ";l=6" m"$

$I=1/12*8*6^2=(8*36)/12=8*3=24$

$I=24*4pi=96 pi$

What is the angular momentum of a rod with a mass of 8 kg8 kg and length of 6 m6 m that is spinning around its center at 2 Hz 2 Hz?