What is the angular momentum of a rod with a mass of $8 kg$ and length of $6 m$ that is spinning around its center at $5 Hz$ ?

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Answer 1 · 2017-03-03T10:35:11

The angular momentum is $=754kgm^2s^-1$

The angular momentum is $L=Iomega$

For a rod (rotating about the center), $I=(mL^2)/12$

So, $I=8*(6)^2/12=24kgm^2$

The angular velocity is

$omega=5*2pi=10pirads^-1$

So,

The angular momentum is

$L=24*10pi=754kgm^2s^-1$

What is the angular momentum of a rod with a mass of 8 kg8 kg and length of 6 m6 m that is spinning around its center at 5 Hz5 Hz?