What is the angular momentum of a rod with a mass of $8 kg$ and length of $6 m$ that is spinning around its center at $3 6 Hz$ ?

Question

1406 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-08T20:10:25

$1728\pi=5428.6$ #kg.m^2/s#

The moment-of-inertia of a rod of mass $M$ and length $L$ rotating about its centre is $I=1/12 ML^2=1/12(8kg)(6m)^2=24kg.m^2$ .

The angular frequency $\omega$ is related to the frequency $f$ as $\omega = 2\pi f=2\pi*(36Hz)=72\pi$ rad/s,

Angular Momentum : The magnitude of Angular Momentum vector is $L=I\omega = I.2\pi f=(24 kg.m^2)*(72\pi)=1728\pi$ #kg.m^2/s#

What is the angular momentum of a rod with a mass of 8 kg8 kg and length of 6 m6 m that is spinning around its center at 3 6 Hz 3 6 Hz?