What is the angular momentum of a rod with a mass of $5 k g$ $5 kg$ and length of $4 m$ $4 m$ that is spinning around its center at $21 H z$ $2 1 Hz$ ?

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Answer 1 · 2017-08-08T12:10:35

The angular momentum is $= 879.6 k g m^{2} s^{- 1}$ $=879.6kgm^2s^-1$

The angular momentum is $L = I ω$ $L=Iomega$

where $I$ $I$ is the moment of inertia

The moment of inertia of a rod, rotating about the center is

$I = \frac{1}{12} \cdot m L^{2}$ $I=1/12*mL^2$

$= \frac{1}{12} \cdot 5 \cdot 4^{2} = \frac{20}{3} k g m^{2}$ $=1/12*5*4^2= 20/3 kgm^2$

The angular velocity is

$ω = 2 π f = 2 \cdot 21 π = 42 π r a d s^{- 1}$ $omega=2pif=2*21pi=42pirads^-1$

The angular velocity is

$L = \frac{20}{3} \cdot 42 π = 879.6 k g m^{2} s^{- 1}$ $L=20/3*42pi=879.6kgm^2s^-1$

What is the angular momentum of a rod with a mass of 5 kg5kg5 kg and length of 4 m4m4 m that is spinning around its center at 2 1 Hz21Hz 2 1 Hz?