What is the angular momentum of a rod with a mass of $5 k g$ $5 kg$ and length of $4 m$ $4 m$ that is spinning around its center at $11 H z$ $1 1 Hz$ ?

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What is the angular momentum of a rod with a mass of $5 k g$ $5 kg$ and length of $4 m$ $4 m$ that is spinning around its center at $11 H z$ $1 1 Hz$ ?

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Answer 1 · 2016-11-04T13:39:54

The angular momentum(L)=5526.4J-s.

Explanation:

Angular momentum $L = m r^{2} (ω)$ $L=mr^2(omega)$
Here the object is rotated on its own centre, so we will be considering its length as radius.
As we know $ω = 2 \times π \times ν$ $omega=2xxpixxnu$
Substitute frequency value in above equation, we get $ω = 69.08 r a \frac{d}{sec}$ $omega=69.08rad /sec$
Now substitute the angular velocity( $ω$ $omega$ ) value in initial equation, we get $L = 5 k g \times 16 m^{2} \times 69.08 r a \frac{d}{s}$ $L= 5kg×16m^2×69.08rad /s$
$:. L=5526.4$ Joules-sec

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What is the angular momentum of a rod with a mass of $5 k g$ $5 kg$ and length of $4 m$ $4 m$ that is spinning around its center at $11 H z$ $1 1 Hz$ ?

1 Answer

Explanation:

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What is the angular momentum of a rod with a mass of 5 kg5kg5 kg and length of 4 m4m4 m that is spinning around its center at 1 1 Hz11Hz 1 1 Hz?

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Explanation:

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What is the angular momentum of a rod with a mass of $5 k g$ $5 kg$ and length of $4 m$ $4 m$ that is spinning around its center at $11 H z$ $1 1 Hz$ ?