What is the angular momentum of a rod with a mass of $4 kg$ and length of $9 m$ that is spinning around its center at $18 Hz$ ?

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Answer 1 · 2017-10-11T06:07:40

The angular momentum is $=3053.6kgm^2s^-1$

The angular momentum is $L=Iomega$

The mass of the rod is $m=4kg$

The length of the rod is $L=9m$

The moment of inertia of a rod, rotating about the center is

$I=1/12*mL^2$

$=1/12*4*9^2= 27 kgm^2$

The angular velocity is

$omega=2pif=2pi*18=(36pi)rads^-1$

Therefore,

The angular momentum is

$L=27*36pi=3053.6kgm^2s^-1$

What is the angular momentum of a rod with a mass of 4 kg4 kg and length of 9 m9 m that is spinning around its center at 18 Hz18 Hz?