What is the angular momentum of a rod with a mass of $15 k g$ $15 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $23 H z$ $23 Hz$ ?

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What is the angular momentum of a rod with a mass of $15 k g$ $15 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $23 H z$ $23 Hz$ ?

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Answer 1 · 2016-01-19T12:44:46

$\to L = 6503.085 k g . m^{2} / s$ $vecL=6503.085kg.m^2//s$ in direction of $\to r \times \to p$ $vecrxxvecp$ .

Explanation:

The moment of inertia of a thin rod about an axis through its centre is given by (can be proven - ask if you want me to show you the derivation)

$I = \frac{1}{12} M L^{2}$ $I=1/12ML^2$

$= \frac{1}{12} \times 15 \times 6^{2}$ $=1/12xx15xx6^2$

$= 45 k g . m^{2}$ $=45kg.m^2$ .

The angular velocity of the rod is given by

$ω = 2 π f$ $omega=2pif$

$= 2 π \times 23 = 144.513 r a d / s$ $=2pixx23=144.513rad//s$ .

Hence the angular momentum is given by

$L = I ω$ $L=Iomega$

$= 45 \times 144.513$ $=45xx144.513$

$= 6503.085 k g . m^{2} / s$ $=6503.085kg.m^2//s$ .

The direction hereof may be obtained by the right hand rule - curl the fingers of your right hand in the direction of the rotation and your thumb will point in the direction of the angular momentum $\to L$ $vecL$ .

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What is the angular momentum of a rod with a mass of $15 k g$ $15 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $23 H z$ $23 Hz$ ?

1 Answer

Explanation:

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What is the angular momentum of a rod with a mass of 15 kg15kg15 kg and length of 6 m6m6 m that is spinning around its center at 23 Hz23Hz23 Hz?

1 Answer

Explanation:

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What is the angular momentum of a rod with a mass of $15 k g$ $15 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $23 H z$ $23 Hz$ ?