What is tan^2theta/(1-sin^3theta in terms of non-exponential trigonometric functions?

1 Answer
Aug 25, 2016

tan^2theta/(1-sin^3theta)

=sin^2theta/(cos^2theta(1-sin^3theta))

=(8sin^2theta)/(8cos^2theta-8cos^2thetasin^3theta)

=(8sin^2theta)/(8cos^2theta-2xx(2costhetasintheta)^2sintheta

=(8sin^2theta)/(8cos^2theta-2sin^2(2theta)sintheta

=(4(1-cos2theta))/(4(1+cos2theta)-(1-cos(4theta))sintheta)