What is $tan^2theta/(1-sin^3theta$ in terms of non-exponential trigonometric functions?

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Answer 1 · 2016-08-25T17:21:07

$tan^2theta/(1-sin^3theta)$

$=sin^2theta/(cos^2theta(1-sin^3theta))$

$=(8sin^2theta)/(8cos^2theta-8cos^2thetasin^3theta)$

$=(8sin^2theta)/(8cos^2theta-2xx(2costhetasintheta)^2sintheta$

$=(8sin^2theta)/(8cos^2theta-2sin^2(2theta)sintheta$

$=(4(1-cos2theta))/(4(1+cos2theta)-(1-cos(4theta))sintheta)$

What is tan^2theta/(1-sin^3thetatan^2theta/(1-sin^3theta in terms of non-exponential trigonometric functions?