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What is ${sec}^{2} θ$ $sec^2theta$ in terms of non-exponential trigonometric functions?

1 Answer

Dec 8, 2015

Transform ${sec}^{2} x$ $sec^2 x$

Explanation:

${sec}^{2} x = \frac{1}{{cos}^{2} x} = \frac{2}{1 + cos 2 x}$ $sec^2 x = 1/(cos^2 x) = 2/(1 + cos 2x)$

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