What is #(root9(8) )/(root12(16)# in simplified radical form? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Shwetank Mauria Jun 13, 2016 #root(9)8/root(12)16=1# Explanation: #root(9)8/root(12)16# = #root(9)(2^3)/root(12)(2^4)# = #(2^3)^(1/9)/(2^4)^(1/12# = #(2^(3xx1/9))/(2^(4xx1/12))# = #2^(1/3)/2^(1/3)# = #1# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 799 views around the world You can reuse this answer Creative Commons License