What is $h (f (- 2))$ $h(f(-2))$ given $f (x) = x^{2}$ $f(x)=x^2$ and $h (x) = x + 4$ $h(x)=x+4$ ?

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Answer 1 · 2016-12-28T03:23:43

$h (f (- 2)) = 8$ $h(f(-2)) = 8$

To solve $h (f (- 2))$ $color(blue)(h(color(red)(f(-2))))$ we can first solve the function $f (- 2)$ $color(red)(f(-2))$

$f (- 2) = {(- 2)}^{2} = 4$ $color(red)(f(-2)) = (-2)^2 = 4$

$h (f (- 2))$ $color(blue)(h(color(red)(f(-2))))$ now becomes $h (4)$ $color(blue)(h(color(red)(4)))$

$h (4) = 4 + 4 = 8$ $color(blue)(h(color(red)(4))) = 4 + 4 = 8$

What is h(f(-2))h(f(−2))h(f(-2)) given f(x)=x^2f(x)=x2f(x)=x^2 and h(x)=x+4h(x)=x+4h(x)=x+4?