What is (dy)/(dx)dydx of sqrt(y/x)+sqrt(x/y)=sqrta???yx+xy=a???

2 Answers
Mar 3, 2018

I am confused something still I answered.

Explanation:

![My http://notebook...](https://useruploads.socratic.org/f7HD0xiERVOGEPbBftUy_New_Doc_2018-03-03_1%5B1%5D.jpg)

  • I took aa as constant.
  • Used the rule ul(bar(|color(red)(d/(dx)(uv)=(v cdot (du)/(dx)-v cdot (dv)/(dx))/v^2))|
Mar 3, 2018

See below.

Explanation:

Making y = lambda^2 x and substituting

lambda+1/lambda = sqrta or

lambda^2-sqrta lambda + 1 = 0

now solving for lambda

lambda =1/2( sqrta pm sqrt(a-4)) so

y/x = 1/4( sqrta pm sqrt(a-4))^2

and then

dy/dx = 1/4( sqrta pm sqrt(a-4))^2

for a > 4

Attached a plot for

sqrt(y/x)+sqrt(x/y) = 2.3

enter image source here