What is $\frac{csc θ}{8}$ $(csctheta)/8$ in terms of $tan θ$ $tantheta$ ?

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Answer 1 · 2016-02-19T12:00:33

$\frac{\sqrt{{tan}^{2} θ + 1}}{8 tan θ}$ $sqrt(tan^2theta+1)/(8tantheta)$

$\frac{csc θ}{8}$ $csctheta/8$

= $\frac{\sqrt{{csc}^{2} θ}}{8}$ $sqrt(csc^2theta)/8$

= $\frac{\sqrt{1 + {cot}^{2} θ}}{8}$ $sqrt(1+cot^2theta)/8$

= $\frac{\sqrt{1 + \frac{1}{{tan}^{2} θ}}}{8}$ $sqrt(1+1/tan^2theta)/8$

= $\frac{\sqrt{{tan}^{2} θ + 1}}{8 tan θ}$ $sqrt(tan^2theta+1)/(8tantheta)$

What is (csctheta)/8cscθ8(csctheta)/8 in terms of tanthetatanθtantheta?