What is ${cos}^{2} θ - sec θ$ $cos^2theta-sectheta$ in terms of $sin θ$ $sintheta$ ?

Question

1447 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-01T07:47:20

${cos}^{2} θ - sec θ = 1 - {sin}^{2} θ - \frac{1}{\sqrt{1 - {sin}^{2} θ}}$ $cos^2theta-sectheta=1-sin^2theta-1/sqrt(1-sin^2theta)$

${cos}^{2} θ - sec θ$ $cos^2theta-sectheta$

= $1 - {sin}^{2} θ - \frac{1}{cos θ}$ $1-sin^2theta-1/costheta$

= $1 - {sin}^{2} θ - \frac{1}{\sqrt{{cos}^{2} θ}}$ $1-sin^2theta-1/sqrt(cos^2theta)$

= $1 - {sin}^{2} θ - \frac{1}{\sqrt{1 - {sin}^{2} θ}}$ $1-sin^2theta-1/sqrt(1-sin^2theta)$

What is cos2θ−secθcos^2theta-sectheta in terms of sinθsintheta?