What is 6 ?divided by the square root of three in simplest radical form Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer GiĆ³ Apr 3, 2017 This is the best I got.... Explanation: #6/sqrt(3)*(sqrt(3)/sqrt(3))=# rationalizing: #=(6sqrt(3))/3=2sqrt(3)=sqrt(2^2*3)=sqrt(12)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 19488 views around the world You can reuse this answer Creative Commons License