What is 6 ?divided by the square root of three in simplest radical form Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer GiĆ³ Apr 3, 2017 This is the best I got.... Explanation: 6/sqrt(3)*(sqrt(3)/sqrt(3))= rationalizing: =(6sqrt(3))/3=2sqrt(3)=sqrt(2^2*3)=sqrt(12) Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 21139 views around the world You can reuse this answer Creative Commons License