What is $3csc^2theta-4sec^2theta+cos^2theta$ in terms of non-exponential trigonometric functions?

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Answer 1 · 2016-08-22T04:05:34

$3csc^2theta-4sec^2theta+cos^2theta$

$=6/(2sin^2theta)-8/(2cos^2theta)+cos^2theta$

$=6/(1-cos2theta)-8/(1+cos2theta)+1/2(1+cos2theta)$

What is 3csc^2theta-4sec^2theta+cos^2theta3csc^2theta-4sec^2theta+cos^2theta in terms of non-exponential trigonometric functions?