What is $\frac{- \frac{1}{2}}{\frac{- \sqrt{3}}{2}}$ $(-1/2) / ( [-sqrt3] / 2)$ ?

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Answer 1 · 2015-06-03T05:59:34

Answer: $\frac{- \frac{1}{2}}{- \frac{\sqrt{3}}{2}} = \frac{\sqrt{3}}{3}$ $(-1/2)/(-sqrt(3)/2)=sqrt 3/3$ .

Problem: Solve $\frac{- \frac{1}{2}}{- \frac{\sqrt{3}}{2}}$ $(-1/2)/(-sqrt(3)/2)$ .

Multiply the numerator times the inverse of the denominator.

$-1/cancel2xxcancel2/-sqrt3$ =

$(-1)/-sqrt 3$ =

$1/sqrt 3$

Rationalize the denominator.

$1/sqrt 3xxsqrt3/sqrt3$ =

$sqrt 3/3$

What is (-1/2) / ( [-sqrt3] / 2)−12−√32(-1/2) / ( [-sqrt3] / 2)?