What does pOH mean?

1 Answer
May 26, 2016

pOH = -log_10[HO^-]

Explanation:

So pOH is the basic counterpart of pH (=-log_10[H_3O^+]).

This derives from the autoprotolysis reaction in water:

2H_2O(l) rightleftharpoons H_3O^+ + HO^-

This equilibrium has been carefully measured, and at 298K we write,

K_w=[HO^-][H_3O^+] = 10^-14.

We can take log_10 of both sides to give:

log_10K_w = log_10[HO^-] + log_10[H_3O^+] = log_10{10^-14}

log_10K_w = log_10[HO^-] + log_10[H_3O^+] = -14 (because by definition, log_a(a^b)=b. On rearrangement:

14=-log_10[HO^-] - log_10[H_3O^+]

And, again by definition,

pH + pOH =14

The autoprotolysis of water is a bond breaking reaction. How would you predict K_w to evolve at elevated temperature? What would this mean with respect to pH and pOH?