What are the values of m for which inequality is true? (m+2)e^(-2x)+2(m+2)e^-x+m>0.

1 Answer
Apr 26, 2017

m > 2(1/(e^-x+1)^2-1)

Explanation:

Calling y = e^-x and assuming m ne -2 we have

y^2+2y+m/(m+2) > 0 or

(y+1)^2-1 +m/(m+2) > 0

or

m/(m+2) > 1-(y+1)^2

or

m > 2(1-(y+1)^2)/(y+1)^2

or

m > 2(1/(y+1)^2-1)=2(1/(e^-x+1)^2-1)

Attached a plot showing in light blue the feasible region in the plane x xx m

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