What are the six trig function values of 330?

1 Answer
Nghi N.
May 30, 2018

cos 330 = cos (-30 + 360) = cos (-30) = cos 30 = sqrt3/2
sin 330 = sin (-30 + 360) = sin (-30) = - sin 30 = - 1/2
tan 330 = sin/9cos) = (-1/2)(2/sqrt3) = - 1/sqrt3 = - sqrt3/3
cot 330 = 1/(tan) = - 3/sqrt3 = -sqrt3
sec 330 = 1/(cos) = 2/sqrt3 = 2sqrt3/3
csc 330 =1/(sin) = - 2

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