What are the six trig function values of #(19pi)/3#?

1 Answer
Nghi N.
Nov 4, 2015

Find the six trig functions of #(19pi)/3#

Explanation:

#sin ((19pi)/3) = sin (pi/3 + 6pi) = sin (pi/3) = sqrt3/2#
#cos ((19pi)/3) = cos (pi/3 + 6pi) = cos (pi/3) = 1/2#
#tan ((19pi)/3) = sin/(cos) = (sqrt3/2)(2/1) = sqrt3#
#cot ((19pi)/3) = 1/(tan) = 1/sqrt3 = sqrt3/3#
#sec ((19pi)/3)= 1/(cos) = 2#
#csc ((19pi)/3) = 1/(sin) = 2/sqrt3 = (2sqrt3)/3#

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