What are the six trig function values of #(11pi)/4#?

1 Answer
Nghi N.
Nov 13, 2015

Find the 6 trig function values of #(11pi)/4#

Explanation:

#sin ((11pi)/4) = sin ((3pi)/4 + 2pi) = sin ((3pi)/4) = sqrt2/2#
#cos ((11pi)/4) = cos ((3pi)/4 + 2pi) = cos ((3pi)/4) = -sqrt2/2#
#tan ((11pi)/4) = sin/(cos) = - 1#
#cot ((11p)/4) = 1/(tan) = -1#
#sec ((11pi)/4) = 1/(cos) = 2/sqrt2 = sqrt2#
#csc ((11pi)/4) = 1/(sin) = -2/sqrt2 = -sqrt2#

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