What are the reducing and oxidizing agents in the equation? If there are none, write “no redox reaction" (include oxidation states for each element in the equation)

1 Answer
anor277
Apr 29, 2017

#"Ferric ion"# is reduced..........

Explanation:

And #"oxalate ion"# is oxidized to carbon dioxide.

#"Reduction half equation:"#

#Fe^(3+) + e^(-) rarr Fe^(2+)# #(i)#

#"Oxidation half equation:"#

#""^(+III)C_2O_4^(2-) rarr 2CO_2 +2e^(-)# #(ii)#

For each equation, MANIFESTLY, both charge and mass are balanced, as they must be if they reflect chemical reality, and the final redox equation takes #2xx(i) + (ii):#

#2Fe^(3+) + C_2O_4^(2-)rarr 2Fe^(2+) +2CO_2(g)uarr#

Are charge and mass balanced here? Don't trust my arithmetic!

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