What are the products of a reaction between zinc and silver chlorate?

1 Answer
Andrea B.
Jan 22, 2017

3 Zn + AgClO_3 + 6 HCl = 3 ZnCl_2 + 3 H_2O + AgCl

Explanation:

the reaction doesn't happen between solids but in solution, so you must write in ionic form.

Zn is a reductant and oxidizes to Zn_2+ while the clorate is an oxidant and reduces to Cl^-.

The reactions are the following:
Zn = 2 e+ Zn^(2+)
6 e + ClO_3^- + 6 H^+ = 3 H_2O + Cl^-

Multiplying for three the first reaction and adding the two reaction you obtain:
3 Zn + ClO_3^- + 6 H^+ = 3 Zn^(2+) + 3 H_2O + Cl^-

Ag^+ is usefull only to salificate the anion:
3 Zn + AgClO_3 + 6 H^+ = 3 Zn^(2+) + 3 H_2O + AgCl

To produce the reaction is necessary a strong acid that gives the hydrogen ions, for example HCl, so the reaction may be written:
3 Zn + AgClO_3 + 6 HCl = 3 ZnCl_2 + 3 H_2O + AgCl

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