What are the hydronium and hydroxide ion concentrations in a solution that has a pH of 12.330?

1 Answer
Nathan L.
May 19, 2017

#[H^+] = 4.68 xx 10^-13 M#
#[OH^-] = 0.0214 M#

Explanation:

The #[H^+]# can be found by raising #10# to the power of the negative of the #pH#:

#[H^+] = 10^(-12.330) = 4.68 xx 10^-13 M#

The #[OH^-]# can be found by dividing the value of the ion-product constant for water, #K_w#, by the #[H^+]#:

#[OH^-] = (1.00 xx 10^-14 M)/(4.68 xx 10^-13 M) = 0.0214 M#

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