What are the factors for 2b^4 + 14b^3 - 16b -112?
1 Answer
Mar 26, 2018
Explanation:
"take out a "color(blue)"common factor of 2"
2(b^4+7b^3-8b-56)
"factor "b^4+7b^3-8b-56color(blue)" by grouping"
rArrcolor(red)(b^3)(b+7)color(red)(-8)(b+7)
"take out a common factor "(b+7)
=(b+7)(color(red)(b^3-8))
b^3-8" is a "color(blue)"difference of cubes"
•color(white)(x)a^3-b^3=(a-b)(a^2+ab+b^2)
"here "a=b" and "b=2
rArrb^3-8=(b-2)(b^2+2b+4)
rArr2b^4+14b^3-16b-112
=2(b+7)(b-2)(b^2+2b+4)
