What are the equations in standard form of the equations 9x^2+16y^2=144 and 25x^2+9y^2-18y-216=0 ?

(In ellipses. I don't know how to convert from general form to standard form.)

1 Answer
May 6, 2018

x^2/16 + y^2/9 = 1" " horizontal ellipse centered at (0, 0)

x^2/9 + (y-1)^2/25 = 1" " vertical ellipse centered at (0, 1)

Explanation:

Given: 9x^2 + 16y^2 = 144 and 25x^2 + 9y^2 -18y -216 = 0

To point an ellipse or hyperbola in standard form you must complete the square if needed, then divide by the constant on the right side:

Equation 1: " "(9x^2)/144 + (16y^2)/144 = 144/144

(9x^2)/144 + (16y^2)/144 = 1

Reduce so there isn't a constant in the numerator:

x^2/16 + y^2/9 = 1" " horizontal ellipse centered at (0, 0)

It's horizontal because the largest denominator is on the x-term.

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Equation 2:
Requires completing of the square. First group x terms together, y-terms together and put the constant on the right:

(25x^2) + (9y^2 -18y) = 216

Factor: 25x^2 + 9(y^2 -2y) = 216

Complete the square on y by halving the -2y constant = -1 and adding the 9(-1)^2 on the right that was added to the left when the square was completed:

25x^2 + 9(y-1)^2 = 216 + 9(-1)^2

25x^2 + 9(y-1)^2 = 225

Divide by the constant on the right side:

(25x^2)/225 + (9(y-1)^2)/225 = 225/225

(25x^2)/225 + (9(y-1)^2)/225 =1

Reduce so there isn't a constant in the numerator:

x^2/9 + (y-1)^2/25 =1" " vertical ellipse centered at (0, 1)

It's vertical because the largest denominator is on the y-term.