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What are the critical points of $f(x) = x^2e^x + 2/x^2$ ?

1 Answer

Jan 10, 2018

There is one critical number. It is approximately #0.873

Explanation:

$f'(x) = 2xe^x+x^2e^x-4/x^3$

Using approximation or technology, we find that

$f'(x) = 0$ at about $0.873$

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