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What are the critical points of #f(x) =e^x-x^2e^(x^2)#?

1 Answer

Jul 24, 2017

#f'(x) = e^x -2xe^(x^2) + e^x(2xe^(x^2))#

Explanation:

#(e^x)' = e^x#
#(e^u)' = e^u*u'#

#f(x) = e^x - x^2*e^(x^2)#

use the Product Rule #f'g + fg'# for #x^2*e^(x^2)#
#f'(x) = e^x - (2x)(e^(x^2))+(e^x)(2xe^(x^2))#
#f'(x) = e^x -2xe^(x^2) + e^x(2xe^(x^2))#

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