# What are the critical points of #f(x) =2e^(3x)-3xe^(2x)#?

##### 1 Answer

#### Explanation:

To compute critical points of a function, you need its first derivative.

**Derivative of #2e^{3x}#:**

We need two rules: first of all, the derivative doesn't care about multiplicative factors, so

To compute

The chain rule states that

Which in your case becomes

So, the whole derivative is

**Derivative of #3xe^{2x}#:**

In addition to what we saw before, we need to add the rule for deriving a product of two functions, which is

So, we have that

Finally, sum up the two pieces: we have

And we can factor