What are the asymptotes of y=x/(x^2-9)y=xx29 and how do you graph the function?

1 Answer
Mar 20, 2017

The vertical asymptotes are x=-3x=3 and x=3x=3
The horizontal asymptote is y=0y=0
No oblique asymptote

Explanation:

We need

a^2-b^2=(a+b)(a-b)a2b2=(a+b)(ab)

We factorise the denominator

x^2-9=(x+3)(x-3)x29=(x+3)(x3)

y=x/((x+3)(x-3))y=x(x+3)(x3)

As we cannot divide by 00, x!=3 and x!=3x3

The vertical asymptotes are x=-3x=3 and x=3x=3

There are no oblique asymptotes as the degree of the numerator is << than the degree of the denominator

lim_(x->-oo)y=lim_(x->-oo)x/x^2=lim_(x->-oo)1/x=0^-

lim_(x->+oo)y=lim_(x->+oo)x/x^2=lim_(x->+oo)1/x=0^+

The horizontal asymptote is y=0

We can build a sign chart to have a general view of the graph

color(white)(aaaa)xcolor(white)(aaaa)-oocolor(white)(aaaa)-3color(white)(aaaaaaaa)0color(white)(aaaaaaa)+3color(white)(aaaaaaa)+oo

color(white)(aaaa)x+3color(white)(aaaa)-color(white)(aaa)||color(white)(aaaa)+color(white)(aaaa)+color(white)(aaaaa)||color(white)(aaa)+

color(white)(aaaa)xcolor(white)(aaaaaaaa)-color(white)(aaa)||color(white)(aaaa)-color(white)(aaaa)+color(white)(aaaaa)||color(white)(aaa)+

color(white)(aaaa)x-3color(white)(aaaa)-color(white)(aaa)||color(white)(aaaa)-color(white)(aaaa)-color(white)(aaaaa)||color(white)(aaa)+

color(white)(aaaa)ycolor(white)(aaaaaaaa)-color(white)(aaa)||color(white)(aaaa)+color(white)(aaaa)-color(white)(aaaaa)||color(white)(aaa)+

The intercepts are (0,0)

lim_(x->-3^-)y=-oo

lim_(x->-3^+)y=+oo

lim_(x->3^-)y=-oo

lim_(x->3^+)y=+oo

Here is the graph

graph{(y-(x)/(x^2-9))(y)(y-1000(x+3))(y-1000(x-3))=0 [-18.05, 18.02, -9.01, 9.03]}